Karl Pearson‟s coefficient of skewness of a distribution is +0.32. Its standard deviation is 6.5 and mean is 29.6. Find the mode and median of the distribution.
Given J=+.32, ℴ=65, ӯ=29.6,M=?,Z=? J=ӯ ℴ -z/ ℴ =29.6-Z/6.5=0.32 Or 29.6-Z=0.32×6.5 Or 29.6-Z=2.08 Or -Z=2.08-29.6 Or -Z=27.52 Or Z=27.52 Altranative Formula is :J=3( ӯ-M)/ ℴ Or 0.32=3(29.6-M) 6.5 Or 0.32×6.5=3(29.6-M) Or 2.08 =88.8-M Or...
